11x^2-64x-12=0

Solution for 11x^2-64x-12=0 equation:

11x^2-64x-12=0

a = 11; b = -64; c = -12;
Δ = b2-4ac
Δ = -642-4·11·(-12)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-68}{2*11}=\frac{-4}{22}
=-2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+68}{2*11}=\frac{132}{22}
=6
$